Mercurial > sdl-ios-xcode
view docs/man3/SDL_SemWait.3 @ 1021:ddd058103e28
Date: Sun, 2 Jan 2005 18:36:09 +0100
From: Jon Daniel
Subject: [SDL] KeyRepeat fix
If you switch keys very fast and hold the last one it
doesn't get repeated because the key release of the first key
occured after the key press of the second key.
Unfortunatly the key release of the first key sets
SDL_KeyRepeat.timestamp = 0; causing the the second key not to repeat.
This should be always reproducable. I've only checked this on x86-64
X11.
To fix this I just added another condition to make sure the sym of the
released key matches SDL_KeyRepeat.key.keysym.sym.
author | Sam Lantinga <slouken@libsdl.org> |
---|---|
date | Mon, 03 Jan 2005 00:24:44 +0000 |
parents | e5bc29de3f0a |
children | 546f7c1eb755 |
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.TH "SDL_SemWait" "3" "Tue 11 Sep 2001, 23:00" "SDL" "SDL API Reference" .SH "NAME" SDL_SemWait\- Lock a semaphore and suspend the thread if the semaphore value is zero\&. .SH "SYNOPSIS" .PP \fB#include "SDL\&.h" #include "SDL_thread\&.h" .sp \fBint \fBSDL_SemWait\fP\fR(\fBSDL_sem *sem\fR); .SH "DESCRIPTION" .PP \fBSDL_SemWait()\fP suspends the calling thread until either the semaphore pointed to by \fBsem\fR has a positive value, the call is interrupted by a signal or error\&. If the call is successful it will atomically decrement the semaphore value\&. .PP After \fBSDL_SemWait()\fP is successful, the semaphore can be released and its count atomically incremented by a successful call to \fISDL_SemPost\fR\&. .SH "RETURN VALUE" .PP Returns \fB0\fR if successful or \fB-1\fR if there was an error (leaving the semaphore unchanged)\&. .SH "EXAMPLES" .PP .PP .nf \f(CWif (SDL_SemWait(my_sem) == -1) { return WAIT_FAILED; } \&.\&.\&. SDL_SemPost(my_sem);\fR .fi .PP .SH "SEE ALSO" .PP \fI\fBSDL_CreateSemaphore\fP\fR, \fI\fBSDL_DestroySemaphore\fP\fR, \fI\fBSDL_SemTryWait\fP\fR, \fI\fBSDL_SemWaitTimeout\fP\fR, \fI\fBSDL_SemPost\fP\fR, \fI\fBSDL_SemValue\fP\fR ...\" created by instant / docbook-to-man, Tue 11 Sep 2001, 23:00