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Date: Sun, 2 Jan 2005 18:36:09 +0100 From: Jon Daniel Subject: [SDL] KeyRepeat fix If you switch keys very fast and hold the last one it doesn't get repeated because the key release of the first key occured after the key press of the second key. Unfortunatly the key release of the first key sets SDL_KeyRepeat.timestamp = 0; causing the the second key not to repeat. This should be always reproducable. I've only checked this on x86-64 X11. To fix this I just added another condition to make sure the sym of the released key matches SDL_KeyRepeat.key.keysym.sym.
author Sam Lantinga <slouken@libsdl.org>
date Mon, 03 Jan 2005 00:24:44 +0000
parents e5bc29de3f0a
children 546f7c1eb755
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.TH "SDL_CondWaitTimeout" "3" "Tue 11 Sep 2001, 23:00" "SDL" "SDL API Reference" 
.SH "NAME"
SDL_CondWaitTimeout\- Wait on a condition variable, with timeout
.SH "SYNOPSIS"
.PP
\fB#include "SDL\&.h"
#include "SDL_thread\&.h"
.sp
\fBint \fBSDL_CondWaitTimeout\fP\fR(\fBSDL_cond *cond, SDL_mutex *mutex, Uint32 ms\fR);
.SH "DESCRIPTION"
.PP
Wait on the condition variable \fBcond\fR for, at most, \fBms\fR milliseconds\&. \fBmut\fR is unlocked so it must be locked when the function is called\&. Returns \fBSDL_MUTEX_TIMEDOUT\fP if the condition is not signalled in the allotted time, \fB0\fR if it was signalled or \fB-1\fR on an error\&.
.SH "SEE ALSO"
.PP
\fI\fBSDL_CondWait\fP\fR
...\" created by instant / docbook-to-man, Tue 11 Sep 2001, 23:00