view src/libm/k_cos.c @ 3197:434ce3242e1c

Alexei Tereschenko Why not to use hardware vertex processing instead of software one if it is available in D3D render driver? With hardware processing testsprite2 runs three times faster on all videocards which I could test.
author Sam Lantinga <slouken@libsdl.org>
date Tue, 16 Jun 2009 14:34:15 +0000
parents dc1eb82ffdaa
children
line wrap: on
line source

/* @(#)k_cos.c 5.1 93/09/24 */
/*
 * ====================================================
 * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
 *
 * Developed at SunPro, a Sun Microsystems, Inc. business.
 * Permission to use, copy, modify, and distribute this
 * software is freely granted, provided that this notice
 * is preserved.
 * ====================================================
 */

#if defined(LIBM_SCCS) && !defined(lint)
static const char rcsid[] =
    "$NetBSD: k_cos.c,v 1.8 1995/05/10 20:46:22 jtc Exp $";
#endif

/*
 * __kernel_cos( x,  y )
 * kernel cos function on [-pi/4, pi/4], pi/4 ~ 0.785398164
 * Input x is assumed to be bounded by ~pi/4 in magnitude.
 * Input y is the tail of x.
 *
 * Algorithm
 *	1. Since cos(-x) = cos(x), we need only to consider positive x.
 *	2. if x < 2^-27 (hx<0x3e400000 0), return 1 with inexact if x!=0.
 *	3. cos(x) is approximated by a polynomial of degree 14 on
 *	   [0,pi/4]
 *		  	                 4            14
 *	   	cos(x) ~ 1 - x*x/2 + C1*x + ... + C6*x
 *	   where the remez error is
 *
 * 	|              2     4     6     8     10    12     14 |     -58
 * 	|cos(x)-(1-.5*x +C1*x +C2*x +C3*x +C4*x +C5*x  +C6*x  )| <= 2
 * 	|    					               |
 *
 * 	               4     6     8     10    12     14
 *	4. let r = C1*x +C2*x +C3*x +C4*x +C5*x  +C6*x  , then
 *	       cos(x) = 1 - x*x/2 + r
 *	   since cos(x+y) ~ cos(x) - sin(x)*y
 *			  ~ cos(x) - x*y,
 *	   a correction term is necessary in cos(x) and hence
 *		cos(x+y) = 1 - (x*x/2 - (r - x*y))
 *	   For better accuracy when x > 0.3, let qx = |x|/4 with
 *	   the last 32 bits mask off, and if x > 0.78125, let qx = 0.28125.
 *	   Then
 *		cos(x+y) = (1-qx) - ((x*x/2-qx) - (r-x*y)).
 *	   Note that 1-qx and (x*x/2-qx) is EXACT here, and the
 *	   magnitude of the latter is at least a quarter of x*x/2,
 *	   thus, reducing the rounding error in the subtraction.
 */

#include "math.h"
#include "math_private.h"

#ifdef __STDC__
static const double
#else
static double
#endif
  one = 1.00000000000000000000e+00,     /* 0x3FF00000, 0x00000000 */
    C1 = 4.16666666666666019037e-02,    /* 0x3FA55555, 0x5555554C */
    C2 = -1.38888888888741095749e-03,   /* 0xBF56C16C, 0x16C15177 */
    C3 = 2.48015872894767294178e-05,    /* 0x3EFA01A0, 0x19CB1590 */
    C4 = -2.75573143513906633035e-07,   /* 0xBE927E4F, 0x809C52AD */
    C5 = 2.08757232129817482790e-09,    /* 0x3E21EE9E, 0xBDB4B1C4 */
    C6 = -1.13596475577881948265e-11;   /* 0xBDA8FAE9, 0xBE8838D4 */

#ifdef __STDC__
double attribute_hidden
__kernel_cos(double x, double y)
#else
double attribute_hidden
__kernel_cos(x, y)
     double x, y;
#endif
{
    double a, hz, z, r, qx;
    int32_t ix;
    GET_HIGH_WORD(ix, x);
    ix &= 0x7fffffff;           /* ix = |x|'s high word */
    if (ix < 0x3e400000) {      /* if x < 2**27 */
        if (((int) x) == 0)
            return one;         /* generate inexact */
    }
    z = x * x;
    r = z * (C1 + z * (C2 + z * (C3 + z * (C4 + z * (C5 + z * C6)))));
    if (ix < 0x3FD33333)        /* if |x| < 0.3 */
        return one - (0.5 * z - (z * r - x * y));
    else {
        if (ix > 0x3fe90000) {  /* x > 0.78125 */
            qx = 0.28125;
        } else {
            INSERT_WORDS(qx, ix - 0x00200000, 0);       /* x/4 */
        }
        hz = 0.5 * z - qx;
        a = one - qx;
        return a - (hz - (z * r - x * y));
    }
}