Mercurial > sdl-ios-xcode
view src/video/e_log.h @ 1348:40d0975c1769
Date: Mon, 6 Feb 2006 11:41:04 -0500
From: "mystml@adinet.com.uy"
Subject: [SDL] ALT-F4 using DirectX
My game isn't getting SDL_QUIT when I press ALT-F4 using the DirectX
driver; it does get SDL_QUIT when I press the red X in the window.
I tracked this down to DX5_HandleMessage() in SDL_dx5events.c;
WM_SYSKEYDOWN is being trapped and ignored which causes Windows not to post
a WM_CLOSE, hence no SDL_QUIT is being generated.
The relevant code is this :
/* The keyboard is handled via DirectInput */
case WM_SYSKEYUP:
case WM_SYSKEYDOWN:
case WM_KEYUP:
case WM_KEYDOWN: {
/* Ignore windows keyboard messages */;
}
return(0);
If I comment the WM_SYSKEYDOWN case, it falls through DefWindowProc() and
ALT-F4 starts working again.
I'm not sure about the best way to fix this. One option is handling ALT-F4
as a particular case somehow, but doesn't sound good. Another option would
be to handle WM_SYSKEYDOWN separately and breaking instead of returning 0,
so processing falls through and goes to DefWindowProc which does The Right
Thing (TM). This seems to be the minimal change that makes ALT-F4 work and
normal keyboard input continues to work.
Does this sound reasonable? Am I overlooking anything? Do I submit a patch?
--Gabriel
author | Sam Lantinga <slouken@libsdl.org> |
---|---|
date | Wed, 08 Feb 2006 17:19:43 +0000 |
parents | 450721ad5436 |
children | 782fd950bd46 c121d94672cb |
line wrap: on
line source
/* @(#)e_log.c 5.1 93/09/24 */ /* * ==================================================== * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved. * * Developed at SunPro, a Sun Microsystems, Inc. business. * Permission to use, copy, modify, and distribute this * software is freely granted, provided that this notice * is preserved. * ==================================================== */ #if defined(LIBM_SCCS) && !defined(lint) static char rcsid[] = "$NetBSD: e_log.c,v 1.8 1995/05/10 20:45:49 jtc Exp $"; #endif /* __ieee754_log(x) * Return the logrithm of x * * Method : * 1. Argument Reduction: find k and f such that * x = 2^k * (1+f), * where sqrt(2)/2 < 1+f < sqrt(2) . * * 2. Approximation of log(1+f). * Let s = f/(2+f) ; based on log(1+f) = log(1+s) - log(1-s) * = 2s + 2/3 s**3 + 2/5 s**5 + ....., * = 2s + s*R * We use a special Reme algorithm on [0,0.1716] to generate * a polynomial of degree 14 to approximate R The maximum error * of this polynomial approximation is bounded by 2**-58.45. In * other words, * 2 4 6 8 10 12 14 * R(z) ~ Lg1*s +Lg2*s +Lg3*s +Lg4*s +Lg5*s +Lg6*s +Lg7*s * (the values of Lg1 to Lg7 are listed in the program) * and * | 2 14 | -58.45 * | Lg1*s +...+Lg7*s - R(z) | <= 2 * | | * Note that 2s = f - s*f = f - hfsq + s*hfsq, where hfsq = f*f/2. * In order to guarantee error in log below 1ulp, we compute log * by * log(1+f) = f - s*(f - R) (if f is not too large) * log(1+f) = f - (hfsq - s*(hfsq+R)). (better accuracy) * * 3. Finally, log(x) = k*ln2 + log(1+f). * = k*ln2_hi+(f-(hfsq-(s*(hfsq+R)+k*ln2_lo))) * Here ln2 is split into two floating point number: * ln2_hi + ln2_lo, * where n*ln2_hi is always exact for |n| < 2000. * * Special cases: * log(x) is NaN with signal if x < 0 (including -INF) ; * log(+INF) is +INF; log(0) is -INF with signal; * log(NaN) is that NaN with no signal. * * Accuracy: * according to an error analysis, the error is always less than * 1 ulp (unit in the last place). * * Constants: * The hexadecimal values are the intended ones for the following * constants. The decimal values may be used, provided that the * compiler will convert from decimal to binary accurately enough * to produce the hexadecimal values shown. */ /*#include "math.h"*/ #include "math_private.h" #ifdef __STDC__ static const double #else static double #endif ln2_hi = 6.93147180369123816490e-01, /* 3fe62e42 fee00000 */ ln2_lo = 1.90821492927058770002e-10, /* 3dea39ef 35793c76 */ Lg1 = 6.666666666666735130e-01, /* 3FE55555 55555593 */ Lg2 = 3.999999999940941908e-01, /* 3FD99999 9997FA04 */ Lg3 = 2.857142874366239149e-01, /* 3FD24924 94229359 */ Lg4 = 2.222219843214978396e-01, /* 3FCC71C5 1D8E78AF */ Lg5 = 1.818357216161805012e-01, /* 3FC74664 96CB03DE */ Lg6 = 1.531383769920937332e-01, /* 3FC39A09 D078C69F */ Lg7 = 1.479819860511658591e-01; /* 3FC2F112 DF3E5244 */ #ifdef __STDC__ double __ieee754_log(double x) #else double __ieee754_log(x) double x; #endif { double hfsq,f,s,z,R,w,t1,t2,dk; int32_t k,hx,i,j; u_int32_t lx; EXTRACT_WORDS(hx,lx,x); k=0; if (hx < 0x00100000) { /* x < 2**-1022 */ if (((hx&0x7fffffff)|lx)==0) return -two54/zero; /* log(+-0)=-inf */ if (hx<0) return (x-x)/zero; /* log(-#) = NaN */ k -= 54; x *= two54; /* subnormal number, scale up x */ GET_HIGH_WORD(hx,x); } if (hx >= 0x7ff00000) return x+x; k += (hx>>20)-1023; hx &= 0x000fffff; i = (hx+0x95f64)&0x100000; SET_HIGH_WORD(x,hx|(i^0x3ff00000)); /* normalize x or x/2 */ k += (i>>20); f = x-1.0; if((0x000fffff&(2+hx))<3) { /* |f| < 2**-20 */ if(f==zero) {if(k==0) return zero; else {dk=(double)k; return dk*ln2_hi+dk*ln2_lo;} } R = f*f*(0.5-0.33333333333333333*f); if(k==0) return f-R; else {dk=(double)k; return dk*ln2_hi-((R-dk*ln2_lo)-f);} } s = f/(2.0+f); dk = (double)k; z = s*s; i = hx-0x6147a; w = z*z; j = 0x6b851-hx; t1= w*(Lg2+w*(Lg4+w*Lg6)); t2= z*(Lg1+w*(Lg3+w*(Lg5+w*Lg7))); i |= j; R = t2+t1; if(i>0) { hfsq=0.5*f*f; if(k==0) return f-(hfsq-s*(hfsq+R)); else return dk*ln2_hi-((hfsq-(s*(hfsq+R)+dk*ln2_lo))-f); } else { if(k==0) return f-s*(f-R); else return dk*ln2_hi-((s*(f-R)-dk*ln2_lo)-f); } }