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view docs/man3/SDL_CondWaitTimeout.3 @ 2318:0c653886cce7

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HandleEvent() returns done each time it is called. If done was set to 0 the program should quit, but because done is not checked until *all* events are handled a following event can reset done to 1 and prevent the program from terminating when told to. I fixed the while loop that handles events to check for the state of done after handling each event. That could leave some events unhandled when the program exits, but it ensures that the program will exit.
author Bob Pendleton <bob@pendleton.com>
date Wed, 20 Feb 2008 23:27:33 +0000
parents 546f7c1eb755
children 1238da4a7112
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.TH "SDL_CondWaitTimeout" "3" "Tue 11 Sep 2001, 23:00" "SDL" "SDL API Reference" 
.SH "NAME"
SDL_CondWaitTimeout \- Wait on a condition variable, with timeout
.SH "SYNOPSIS"
.PP
\fB#include "SDL\&.h"
#include "SDL_thread\&.h"
.sp
\fBint \fBSDL_CondWaitTimeout\fP\fR(\fBSDL_cond *cond, SDL_mutex *mutex, Uint32 ms\fR);
.SH "DESCRIPTION"
.PP
Wait on the condition variable \fBcond\fR for, at most, \fBms\fR milliseconds\&. \fBmut\fR is unlocked so it must be locked when the function is called\&. Returns \fBSDL_MUTEX_TIMEDOUT\fP if the condition is not signalled in the allotted time, \fB0\fR if it was signalled or \fB-1\fR on an error\&.
.SH "SEE ALSO"
.PP
\fI\fBSDL_CondWait\fP\fR
...\" created by instant / docbook-to-man, Tue 11 Sep 2001, 23:00