Mercurial > traipse_dev
view orpg/tools/predTextCtrl.py @ 135:dcf4fbe09b70 beta
Traipse Beta 'OpenRPG' {091010-00}
Traipse is a distribution of OpenRPG that is designed to be easy to setup and go. Traipse also makes it easy for developers to work on
code without fear of sacrifice. 'Ornery-Orc' continues the trend of 'Grumpy' and adds fixes to the code. 'Ornery-Orc's main goal is to
offer more advanced features and enhance the productivity of the user.
Update Summary (Beta)
Added Bookmarks
Fix to Remote Admin Commands
Minor fix to text based Server
Fix to Pretty Print, from Core
Fix to Splitter Nodes not being created
Fix to massive amounts of images loading, from Core
Added 'boot' command to remote admin
Added confirmation window for sent nodes
Minor changes to allow for portability to an OpenSUSE linux OS
Miniatures Layer pop up box allows users to turn off Mini labels, from FlexiRPG
Zoom Mouse plugin added
Images added to Plugin UI
Switching to Element Tree
Map efficiency, from FlexiRPG
Added Status Bar to Update Manager
default_manifest.xml renamed to default_upmana.xml
Cleaner clode for saved repositories
New TrueDebug Class in orpg_log (See documentation for usage)
Mercurial's hgweb folder is ported to upmana
**Pretty important update that can help remove thousands of dead children from your gametree.
**Children, <forms />, <group_atts />, <horizontal />, <cols />, <rows />, <height />, etc... are all tags now. Check your gametree and
look for dead children!!
**New Gamtree Recusion method, mapping, and context sensitivity. !!Alpha - Watch out for infinite loops!!
| author | sirebral |
|---|---|
| date | Tue, 10 Nov 2009 14:11:28 -0600 |
| parents | 118fbe111922 |
| children | 9babc183fa47 |
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# Copyright (C) 2001 The OpenRPG Project # # openrpg-dev@lists.sourceforge.net # # This program is free software; you can redistribute it and/or modify # it under the terms of the GNU General Public License as published by # the Free Software Foundation; either version 2 of the License, or # (at your option) any later version. # # This program is distributed in the hope that it will be useful, # but WITHOUT ANY WARRANTY; without even the implied warranty of # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the # GNU General Public License for more details. # # You should have received a copy of the GNU General Public License # along with this program; if not, write to the Free Software # Foundation, Inc., 675 Mass Ave, Cambridge, MA 02139, USA. # -- # # File: predTextCtrl.py # Author: Andrew Bennett # Maintainer: Andrew Bennett # Version: $id:$ # # Description: This file contains an extension to the wxPython wx.TextCtrl that provides predictive word completion # based on a word file loaded at instantiation. Also, it learns new words as you type, dynamically # adjusting a weight for each word based on how often you type it. # ## ## Module Loading ## import string from orpg.orpg_windows import * import wx #wx.SystemSettings.GetMetric(wx.SYS_VSCROLL_X) from wx.lib.expando import ExpandoTextCtrl from orpg.tools.orpg_log import logger, debug # This line added to test CVS commit ## ## Class Definitions ## # This class implements a tree node that represents a letter # # Defines: # __init__(self,filename) # class Letter: def __init__(self,asciiCharIn,parentNodeIn): self.asciiChar = asciiCharIn # should be an ASCII char self.parentNode = parentNodeIn # should be ref to a class Letter self.priority = 0 # should be an int self.mostCommon = self # should be a ref to a class Letter self.children = {} # should be a ref to a dictionary of class Letter def __str__(self): return self.asciiChar # This class implements the tree structure to hold the words # # Defines: # __init__(self,filename) # updateMostCommon(self,target) # setWord(self,wordText,priority,sumFlag) # addWord(self,wordText) # setWord(self,wordText) # setWordPriority(self,wordText,priority) # findWordNode(self,wordText) returns class Letter # findWordPriority(self,wordText) returns int # getPredition(self,k,cur) returns string class LetterTreeClass(object): # Initialization subroutine. # # self : instance of self # filename : name of word file to use # # returns None # # Purpose: Constructor for LetterTree. Basically, it initializes itself with a word file, if present. def __init__(self, singletonKey): if not isinstance(singletonKey, _SingletonKey): raise invalid_argument(_("Use LetterTree() to get access to singleton")) self.rootNode = Letter("",None) # rootNode is a class Letter self.rootNode.children = {} # initialize the children list # updateMostCommon subroutine. # # self : instance of self # target : class Letter that was updated # # Returns None # # Purpose: Updates all of the parent nodes of the target, such that their mostCommon member # points to the proper class Letter, based on the newly updated priorities. def updateMostCommon(self, target): # cur is a class Letter prev = target.parentNode # prev is a class Letter while prev: if prev.mostCommon is None: prev.mostCommon = target else: if target.priority > prev.mostCommon.priority: prev.mostCommon = target prev = prev.parentNode # setWord subroutine. # # self : instance of self # wordText : string representing word to add # priority : integer priority to set the word # sumFlag : if True, add the priority to the existing, else assign the priority # # Returns: None # # Purpose: Sets or increments the priority of a word, adding the word if necessary def setWord(self,wordText,priority = 1,sumFlag = 0): cur = self.rootNode # start from the root for ch in wordText: # for each character in the word if cur.children.has_key(ch): # check to see if we've found a new word cur = cur.children[ch] # if we haven't found a new word, move to the next letter and try again else: # in this clause, we're creating a new branch, as the word is new newLetter = Letter(ch,cur) # create a new class Letter using this ascii code and the current letter as a parent if cur is self.rootNode: # special case: Others expect the top level letters to point to None, not self.rootNode newLetter.parentNode = None cur.children[ch] = newLetter # add the new letter to the list of children of the current letter cur = newLetter # make the new letter the current one for the next time through # at this point, cur is pointing to the last letter of either a new or existing word. if sumFlag: cur.priority += priority # if the caller wants to add to the existing (0 if new) else: cur.priority = priority # else, the set the priority directly self.updateMostCommon(cur) # this will run back through the tree to fix up the mostCommon members # addWord subroutine. # # self : instance of self # wordText : string representing word to add # # Returns: None # # Purpose: Convenience method that wraps setWord. Used to add words known not to exist. def addWord(self,wordText): self.setWord(wordText,priority = 1) # incWord subroutine. # # self : instance of self # wordText : string representing word to add # # Returns: None # # Purpose: Convenience method that wraps setWord. Used to increment the priority of existing words and add new words. # Note: Generally, this method can be used instead of addWord. def incWord(self,wordText): self.setWord(wordText,priority = 1, sumFlag = 1) # setWordPriority subroutine. # # self : instance of self # wordText : string representing word to add # priority: int that is the new priority # # Returns: None # # Purpose: Convenience method that wraps setWord. Sets existing words to priority or adds new words with priority = priority def setWordPriority(self,wordText,priority): self.setWord(wordText,priority = priority) # findWordNode subroutine. # # self : instance of self # wordText : string representing word to add # # Returns: class Letter or None if word isn't found. # # Purpose: Given a word, it returns the class Letter node that corresponds to the word. Used mostly in prep for a call to # getPrediction() def findWordNode(self,wordText): #returns class Letter that represents the last letter in the word cur = self.rootNode # start at the root for ch in wordText: # move through each letter in the word if cur.children.has_key(ch): # if the next letter exists, make cur equal that letter and loop cur = cur.children[ch] else: return None # return None if letter not found return cur # return cur, as this points to the last letter if we got this far # findWordPriority subroutine. # # self : instance of self # wordText : string representing word to add # # Returns: Int representing the word's priority or 0 if not found. # # Purpose: Returns the priority of the given word def findWordPriority(self,wordText): cur = self.findWordNode(wordText) # find the class Letter node that corresponds to this word if cur: return cur.priority # if it was found, return it's priority else: return 0 # else, return 0, meaning word not found def printTree(self, current=None): letters = [] if current is None: current = self.rootNode for l, letter in current.children.iteritems(): letters.append(str(letter)) if letter.children != {}: m = self.printTree(letter) letters.append(m) return letters # getPrediction subroutine. # # self : instance of self # k : ASCII char that was typed # cur : class Letter that points to the current node in LetterTree # # Returns: The predicted text or "" if none found # # Purpose: This is the meat and potatoes of data structure. It takes the "current" Letter node and the next key typed # and returns it's guess of the rest of the word, based on the highest priority letter in the rest of the branch. def getPrediction(self,k,cur): if cur.children.has_key(k) : # check to see if the key typed is a sub branch # If so, make a prediction. Otherwise, do the else at the bottom of # the method (see below). cur = cur.children[k] # set the cur to the typed key's class Letter in the sub-branch backtrace = cur.mostCommon # backtrace is a class Letter. It's used as a placeholder to back trace # from the last letter of the mostCommon word in the # sub-tree up through the tree until we meet ourself at cur. We'll # build the guess text this way returnText = "" # returnText is a string. This will act as a buffer to hold the string # we build. while cur is not backtrace: # Here's the loop. We loop until we've snaked our way back to cur returnText = backtrace.asciiChar + returnText # Create a new string that is the character at backtrace + everything # so far. So, for "tion" we'll build "n","on","ion","tion" as we .. backtrace = backtrace.parentNode # ... climb back towards cur return returnText # And, having reached here, we've met up with cur, and returnText holds # the string we built. Return it. else: # This is the else to the original if. # If the letter typed isn't in a sub branch, then # the letter being typed isn't in our tree, so return "" # return the empty string # End of class LetterTree! class _SingletonKey(object): def __new__(cls, *args, **kwargs): if not hasattr(cls, '_inst'): cls._inst = super(_SingletonKey, cls).__new__(cls, *args, **kwargs) return cls._inst __key = _SingletonKey() LetterTree = LetterTreeClass(__key) # This class extends wx.TextCtrl # # Extends: wx.TextCtrl # # Overrides: # wx.TextCtrl.__init__(self,parent,id,value,size,style,name) # wx.TextCtrl.OnChar(self,Event) # # Defines: # findWord(self,insert,st) class predTextCtrl(ExpandoTextCtrl): # Initialization subroutine. # # self : instance of self # parent: reference to parent window (wxWindow, me-thinks) # id: new Window Id, default to -1 to create new (I think: see docs for wxPython) # value: String that is the initial value the control holds, defaulting to "" # size: defaults to wx.DefaultSize # style: defaults to 0 # name: defaults to "text" # keyHook: must be a function pointer that takes self and a GetKeyCode object # validator: defaults to None # # Note: These parameters are essentially just passed back to the native wx.TextCtrl. # I basically just included (stole) enough of them from chatutils.py to make # it work. Known missing args are pos and validator, which aren't used by # chatutils.py. # # Returns: None # # Purpose: Constructor for predTextCtrl. Calls wx.TextCtrl.__init__ to get default init # behavior and then inits a LetterTree and captures the parent for later use in # passing events up the chain. def __init__(self, parent, id = -1, value = "" , size = wx.DefaultSize, style = 0, name = "text",keyHook = None, validator=None): # Call super() for default behavior if validator: ExpandoTextCtrl.__init__(self, parent, id=id, value=value, size=size, style=style, name=name, validator=validator ) else: ExpandoTextCtrl.__init__(self, parent, id=id, value=value, size=size, style=style, name=name) self.tree = LetterTree # Instantiate a new LetterTree. # TODO: make name of word file an argument. self.parent = parent # Save parent for later use in passing KeyEvents self.cur = self.tree.rootNode # self.cur is a short cut placeholder for typing consecutive chars # It may be vestigal self.keyHook = keyHook # Save the keyHook passed in ExpandoTextCtrl._wrapLine = self._wrapLine def _wrapLine(self, line, dc, width): # Estimate where the control will wrap the lines and # return the count of extra lines needed. # Re writes ExpandoTextCtrl _wrapLine function pte = dc.GetPartialTextExtents(line) width -= wx.SystemSettings.GetMetric(wx.SYS_VSCROLL_X) idx = 0 start = 0 count = 0 spc = -1 while idx < len(pte): if line[idx] == ' ': debug((line)); spc = idx if pte[idx] - start > width: # we've reached the max width, add a new line count += 1 # did we see a space? if so restart the count at that pos if spc != -1: idx = spc + 1 spc = -1 start = pte[idx] else: idx += 1 return count # findWord subroutine. # # self : instance of self # insert: index of last char in st # st : string from insert to the left # # Note: This implementation is about the third one for this method. Originally, # st was an arbitrary string and insert was the point within # this string to begin looking left. Since, I finally got it # to work right as it is around 2 in the morning, I'm not touching it, for now. # # Returns: String that is the word or "" if none found. This generally doesn't # happen, as st usually ends in a letter, which will be returned. # # Purpose: This function is generally used to figure out the beginning of the # current word being typed, for later use in a LetterTree.getPrediction() def findWord(self, insert, st): # Good luck reading this one. Basically, I started out with an idea, and fiddled with the # constants as best I could until it worked. It's not a piece of work of which I'm too # proud. Basically, it's intent is to check each character to the left until it finds one # that isn't a letter. If it finds such a character, it stops and returns the slice # from that point to insert. Otherwise, it returns the whole thing, due to begin being # initialized to 0 begin = 0 for offset in range(insert - 1): if st[-(offset + 2)] not in string.letters: begin = insert - (offset + 1) break return st[begin:insert] # OnChar subroutine. # # self : instance of self # event: a GetKeyCode object # # Returns: None # # Purpose: This function is the key event handler for predTextCtrl. It handles what it # needs to and passes the event on to it's parent's OnChar method. def OnChar(self,event): # Before we do anything, call the keyHook handler, if not None # This is currently used to implement the typing/not_typing messages in a manner that # doesn't place the code here. Maybe I should reconsider that. :) if(self.keyHook): if self.keyHook(event) == 1: # if the passed in keyHook routine returns a one, it wants no predictive behavior self.parent.OnChar(event) return # This bit converts the GetKeyCode() return (int) to a char if it's in a certain range asciiKey = "" if (event.GetKeyCode() < 256) and (event.GetKeyCode() > 19): asciiKey = chr(event.GetKeyCode()) if asciiKey == "": # If we didn't convert it to a char, then process based on the int GetKeyCodes if event.GetKeyCode() == wx.WXK_TAB: # We want to hook tabs to allow the user to signify acceptance of a # predicted word. # Handle Tab key fromPos = toPos = 0 # get the current selection range (fromPos,toPos) = self.GetSelection() if (toPos - fromPos) == 0: # if there is no selection, pass tab on self.parent.OnChar(event) return else: # This means at least one char is selected self.SetInsertionPoint(toPos) # move the insertion point to the end of the selection self.SetSelection(toPos,toPos) # and set the selection to no chars # The prediction, if any, had been inserted into the text earlier, so # moving the insertion point to the spot directly afterwards is # equivalent to acceptance. Without this, the next typed key would # clobber the prediction. return # Don't pass tab on in this case elif event.GetKeyCode() == wx.WXK_RETURN and event.ShiftDown(): logger.exception('Shift + Enter Not completed, 439, predtextCtrl', True) st = self.GetValue() st += '<br />' return elif event.GetKeyCode() == wx.WXK_RETURN: # We want to hook returns, so that we can update the word list st = self.GetValue() # Grab the text from the control newSt = "" # Init a buffer # This block of code, by popular demand, changes the behavior of the control to ignore any prediction that # hasn't been "accepted" when the enter key is struck. (startSel,endSel) = self.GetSelection() # get the curren selection # # Start update # Changed the following to allow for more friendly behavior in # a multilined predTextCtrl. # # front = st[:startSel] # Slice off the text to the front of where we are # back = st[endSel:] # Slice off the text to the end from where we are # st = front + back # This expression creates a string that get rid of any selected text. # self.SetValue(st) self.Remove( startSel, endSel ) st = string.strip( self.GetValue() ) # # End update # # this loop will walk through every character in st and add it to # newSt if it's a letter. If it's not a letter, (e.g. a comma or # hyphen) a space is added to newSt in it's place. for ch in st: if ch not in string.letters: newSt += " " else: newSt += ch # Now that we've got a string of just letter sequences (words) and spaces # split it and to a LetterTree.incWord on the lowercase version of it. # Reminder: incWord will increment the priority of existing words and add # new ones for aWord in string.split(newSt): self.tree.incWord(string.lower(aWord)) self.parent.OnChar(event) # Now that all of the words are added, pass the event and return return # We want to capture the right arrow key to fix a slight UI bug that occurs when one right arrows # out of a selection. I set the InsertionPoint to the beginning of the selection. When the default # right arrow event occurs, the selection goes away, but the cursor is in an unexpected location. # This snippet fixes this behavior and then passes on the event. elif event.GetKeyCode() == wx.WXK_RIGHT: (startSel,endSel) = self.GetSelection() self.SetInsertionPoint(endSel) self.parent.OnChar(event) return # Ditto as wx.WXK_RIGHT, but for completeness sake elif event.GetKeyCode() == wx.WXK_LEFT: (startSel,endSel) = self.GetSelection() self.SetInsertionPoint(startSel) self.parent.OnChar(event) return else: # Handle any other non-ascii events by calling parent's OnChar() self.parent.OnChar(event) #Call super.OnChar to get default behavior return elif asciiKey in string.letters: # This is the real meat and potatoes of predTextCtrl. This is where most of the # wx.TextCtrl logic is changed. (startSel,endSel) = self.GetSelection() # get the curren selection st = self.GetValue() # and the text in the control front = st[:startSel] # Slice off the text to the front of where we are back = st[endSel:] # Slice off the text to the end from where we are st = front + asciiKey + back # This expression creates a string that will insert the # typed character (asciiKey is generated at the # beginning of OnChar()) into the text. If there # was text selected, that text will not be part # of the new string, due to the way front and back # were sliced. insert = startSel + 1 # creates an int that denotes where the new InsertionPoint # should be. curWord = "" # Assume there's a problem with finding the curWord if (len(back) == 0) or (back[0] not in string.letters): # We should only insert a prediction if we are typing # at the end of a word, not in the middle. There are # three cases: we are typing at the end of the string or # we are typing in the middle of the string and the next # char is NOT a letter or we are typing in the middle of the # string and the next char IS a letter. Only the former two # cases denote that we should make a prediction # Note: The order of the two logical clauses here is important! # If len(back) == 0, then the expression back[0] will # blow up with an out of bounds array subscript. Luckily # the or operator is a short-circuit operator and in this # case will only evaluate back[0] if len(back) != 0, in # which we're safely in bounds. curWord = self.findWord(insert,front + asciiKey) # Now that we know we're supposed to make a prediction, # let's find what word root to use in our prediction. # Note: This is using the confusing findWord method. I # send it insert and the text from the beginning # of the text through the key just entered. This is # NOT the original usage, but it does work. See # findWord() for more details. else: # Here, we've found we're in the middle of a word, so we're # going to call the parent's event handler. self.parent.OnChar(event) return if curWord == "": # Here, we do a quick check to make sure we have a good root # word. If not, allow the default thing to happen. Of course, # now that I'm documenting this, it occurs to me to wonder why # I didn't do the same thing I just talked about. Hmmmmmm. self.parent.OnChar(event) # we're done here return self.cur = self.tree.findWordNode(string.lower(curWord[:-1])) # Still with me? We're almost done. At this point, we # need to convert our word string to a Letter node, # because that's what getPrediction expects. Notice # that we're feeding in the string with the last # char sliced off. For developmentally historical # reasons, getPrediction wants the node just before # the typed character and the typed char separately. if self.cur is None: self.parent.OnChar(event) # if there's no word or no match, we're done return # get the prediction predictText = self.tree.getPrediction(string.lower(asciiKey),self.cur) # This is the big prediction, as noted above # Note the use of string.lower() because we # keep the word list in all lower case,but we # want to be able to match any capitalization if predictText == "": self.parent.OnChar(event) # if there's no prediction, we're done return # And now for the big finale. We're going to take the string st # we created earlier and insert the prediction right after the # newly typed character. front = st[:insert] # Grab a new front from st back = st[insert:] # Grab a new back st = front + predictText + back # Insert the prediction self.SetValue(st) # Now, overwrite the controls text with the new text self.SetInsertionPoint(insert) # Set the proper insertion point, directly behind the # newly typed character and directly in front of the # predicted text. self.SetSelection(insert,insert+len(predictText)) # Very important! Set the selection to encompass the predicted # text. This way, the user can ignore the prediction by simply # continuing to type. Remember, if the user wants the prediction # s/he must strike the tab key at this point. Of course, one could # just use the right arrow key as well, but that's not as easy to # reach. return # Done! Do NOT pass the event on at this point, because it's all done. else: # Handle every other non-letter ascii (e.g. semicolon) by passing the event on. self.parent.OnChar(event) #Call super.OnChar to get default behavior return # End of class predTextCtrl!