view bGrease/color.py @ 144:86b9b181ad1c

Added drag and drop and context menu to the equipment part of the character screen.
author KarstenBock@gmx.net
date Sun, 09 Oct 2011 19:24:37 +0200
parents ff3e395abf91
children a6bbb732b27b
line wrap: on
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class RGBA(object):
	"""Four channel color representation.

	RGBA colors are floating point color representations with color channel
	values between (0..1). Colors may be initialized from 3 or 4 floating
	point numbers or a hex string::

		RGBA(1.0, 1.0, 1.0) # Alpha defaults to 1.0
		RGBA(1.0, 1.0, 0, 0.5)
		RGBA("#333")
		RGBA("#7F7F7F")
	
	Individual color channels can be accessed by attribute name, or the
	color object can be treated as a sequence of 4 floats.
	"""

	def __init__(self, r_or_colorstr, g=None, b=None, a=None):
		if isinstance(r_or_colorstr, str):
			assert g is b is a is None, "Ambiguous color arguments" 
			self.r, self.g, self.b, self.a = self._parse_colorstr(r_or_colorstr)
		elif g is b is a is None:
			try:
				self.r, self.g, self.b, self.a = r_or_colorstr
			except ValueError:
				self.r, self.g, self.b = r_or_colorstr
				self.a = 1.0
		else:
			self.r = r_or_colorstr
			self.g = g
			self.b = b
			self.a = a
		if self.a is None:
			self.a = 1.0
	
	def _parse_colorstr(self, colorstr):
		length = len(colorstr)
		if not colorstr.startswith("#") or length not in (4, 5, 7, 9):
			raise ValueError("Invalid color string: " + colorstr)
		if length <= 5:
			parsed = [int(c*2, 16) / 255.0 for c in colorstr[1:]]
		else:
			parsed = [int(colorstr[i:i+2], 16) / 255.0 for i in range(1, length, 2)]
		if len(parsed) == 3:
			parsed.append(1.0)
		return parsed
	
	def __len__(self):
		return 4
	
	def __getitem__(self, item):
		return (self.r, self.g, self.b, self.a)[item]
	
	def __iter__(self):
		return iter((self.r, self.g, self.b, self.a))
	
	def __eq__(self, other):
		return tuple(self) == tuple(other)
	
	def __repr__(self):
		return "%s(%.2f, %.2f, %.2f, %.2f)" % (self.__class__.__name__, 
			self.r, self.g, self.b, self.a)