Mercurial > parpg-source
view bGrease/color.py @ 99:6e4daff93e7d
If Items in containers or being equipped have no type the game will now try to get the object using the ID.
author | KarstenBock@gmx.net |
---|---|
date | Wed, 28 Sep 2011 12:58:18 +0200 |
parents | ff3e395abf91 |
children | a6bbb732b27b |
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class RGBA(object): """Four channel color representation. RGBA colors are floating point color representations with color channel values between (0..1). Colors may be initialized from 3 or 4 floating point numbers or a hex string:: RGBA(1.0, 1.0, 1.0) # Alpha defaults to 1.0 RGBA(1.0, 1.0, 0, 0.5) RGBA("#333") RGBA("#7F7F7F") Individual color channels can be accessed by attribute name, or the color object can be treated as a sequence of 4 floats. """ def __init__(self, r_or_colorstr, g=None, b=None, a=None): if isinstance(r_or_colorstr, str): assert g is b is a is None, "Ambiguous color arguments" self.r, self.g, self.b, self.a = self._parse_colorstr(r_or_colorstr) elif g is b is a is None: try: self.r, self.g, self.b, self.a = r_or_colorstr except ValueError: self.r, self.g, self.b = r_or_colorstr self.a = 1.0 else: self.r = r_or_colorstr self.g = g self.b = b self.a = a if self.a is None: self.a = 1.0 def _parse_colorstr(self, colorstr): length = len(colorstr) if not colorstr.startswith("#") or length not in (4, 5, 7, 9): raise ValueError("Invalid color string: " + colorstr) if length <= 5: parsed = [int(c*2, 16) / 255.0 for c in colorstr[1:]] else: parsed = [int(colorstr[i:i+2], 16) / 255.0 for i in range(1, length, 2)] if len(parsed) == 3: parsed.append(1.0) return parsed def __len__(self): return 4 def __getitem__(self, item): return (self.r, self.g, self.b, self.a)[item] def __iter__(self): return iter((self.r, self.g, self.b, self.a)) def __eq__(self, other): return tuple(self) == tuple(other) def __repr__(self): return "%s(%.2f, %.2f, %.2f, %.2f)" % (self.__class__.__name__, self.r, self.g, self.b, self.a)